Regular Expression "S" Metacharacter in Java

The subexpression/metacharacter “\S” matches the non-white space characters.

Example 1

import java.util.regex.Matcher; import java.util.regex.Pattern; public class RegexExample {    public static void main( String args[] ) {       String regex = "\S";       String input = "Hello how are you welcome to Tutorialspoint !";       Pattern p = Pattern.compile(regex);       Matcher m = p.matcher(input);       int count = 0;       while(m.find()) {          count++;       }       System.out.println("Number of matches: "+count);    } }

Output

Number of matches: 38

Example 2

import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Example {    public static void main( String args[] ) {       String regex = "\S";       Scanner sc = new Scanner(System.in);       System.out.println("Enter 5 input strings: ");       String input[] = new String[5];       for (int i=0; i<5; i++) {          input[i] = sc.nextLine();       }       //Creating a Pattern object       Pattern p = Pattern.compile(regex);       System.out.println("Number of characters in each string w/o spaces: ");       for(int i=0; i<5;i++) {          //Creating a Matcher object          Matcher m = p.matcher(input[i]);          int count = 0;          while(m.find()) {             count++;          }          System.out.println("String "+i+": "+count);       }    } }

Output

Enter 5 input strings: sample123 test data test *123 ab bc cd de hello how are you welcome to Tutorialspoint Number of characters in each string w/o spaces: String 0: 9 String 1: 8 String 2: 8 String 3: 8 String 4: 37