Python – Test if tuple list has a single element

When it is required to test if a tuple list contains a single element, a flag value and a simple iteration is used.

Example

Below is a demonstration of the same

my_list = [(72, 72, 72), (72, 72), (72, 72)] print("The list is :") print(my_list) my_result = True for sub in my_list:    flag = True    for element in sub:       if element != my_list[0][0]:          flag = False          break    if not flag:       my_result = False       break if(flag == True): print("The tuple contains a single element") else: print("The tuple doesn't contain a single element")

Output

The list is : [(72, 72, 72), (72, 72), (72, 72)] The tuple contains a single element

Explanation

• A list of list is defined and is displayed on the console.

• A variable is assigned to ‘True’.

• The list is iterated over, and a value is flagged as ‘True’.

• If an element of the list is not equal to the first element of the list, the value is flagged to ‘False’.

• Otherwise, the variable is changed to ‘False.

• The control is broken outpf the loop.

• Outside the method, if the flagged value is ‘True’, it means the list contains a single element only.

• Relevant message is displayed on the console.