Python – Test if all rows contain any common element with other Matrix

When it is required to test if all rows contain any common element with other matrix, a simple iteration and a flag value are used.

Example

Below is a demonstration of the same

my_list_1 = [[3, 16, 1], [2, 4], [4, 31, 31]] my_list_2 = [[42, 16, 12], [42, 8, 12], [31, 7, 10]] print("The first list is :") print(my_list_1) print("The second list is :") print(my_list_2) my_result = True for idx in range(0, len(my_list_1)):    temp = False    for element in my_list_1[idx]:       if element in my_list_2[idx]:          temp = True          break    if not temp :       my_result = False       break if(temp == True):    print("The two matrices contain common elements") else:    print("The two matrices don't contain common elements")

Output

The first list is : [[3, 16, 1], [2, 4], [4, 31, 31]] The second list is : [[42, 16, 12], [42, 8, 12], [31, 7, 10]] The two matrices don't contain common elements

Explanation

• Two lists of lists are defined and are displayed on the console.

• A variable is set to Boolean ‘True’.

• The first list is iterated and a temporary variable is set to Boolean ‘False’.

• If the element is present in the second list, then the temporary variable is set to Boolean ‘True’.

• The control breaks out of the loop.

• If the temporary variable is False outside the loop, the control breaks out of the loop.

• In the end, based on the value of the temporary variable, the relevant message is displayed on the console.