Python - Restrict Tuples by frequency of first element’s value

When it is required to restrict the tuples by frequency of first element’s value, a simple ‘if’ condition along with an iteration and ‘append’ method is used.

Example

Below is a demonstration of the same

my_list = [(21, 24), (13, 42), (11, 23), (32, 43), (25, 56),(73, 84), (91, 40), (40, 83), (13, 27)] print("The list is :") print(my_list) my_key = 1 my_result = [] mems = dict() for sub in my_list: if sub[0] not in mems.keys(): mems[sub[0]] = 1 else: mems[sub[0]] += 1 if mems[sub[0]] <= my_key: my_result.append(sub) print("The filtered tuples are :") print(my_result)

Output

The list is : [(21, 24), (13, 42), (11, 23), (32, 43), (25, 56), (73, 84), (91, 40), (40, 83), (13, 27)] The filtered tuples are : [(21, 24), (13, 42), (11, 23), (32, 43), (25, 56), (73, 84), (91, 40), (40, 83)]

Explanation

• A list of tuples is defined and is displayed on the console.

• An integer value is assigned to 1.

• An empty list is defined.

• An empty dictionary is created.

• The list of tuple is iterated over, and if an element is not found in the key value of the dictionary, the 0^th index is assigned to 1.

• Otherwise, it is incremented by 1.

• If it is less than or equal to the key, the element is appended to the empty result.

• This result is the output that is displayed on the console.