Python program to extract rows with common difference elements

When it is required to extract rows with common difference elements, an iteration and a flag value is used.

Example

Below is a demonstration of the same

my_list = [[31, 27, 10], [8, 11, 12], [11, 12, 13], [6, 9, 10]] print("The list is :") print(my_list) my_result = [] for row in my_list:    temp = True    for index in range(0, len(row) - 1): if row[index + 1] - row[index] != row[1] - row[0]: temp = False break if temp : my_result.append(row) print("The resultant list is :") print(my_result)

Output

The list is : [[31, 27, 10], [8, 11, 12], [11, 12, 13], [6, 9, 10]] The resultant list is : [[11, 12, 13]]

Explanation

• A list of tuple is defined and is displayed on the console.

• An empty list is created.

• The list is iterated over, and a variable is assigned to ‘True’.

• The indices are also iterated over.

• If the difference between previous index and current index is not equal to the difference between the previous element and current element, the variable is assigned ‘False’.

• The control breaks out of it.

• In the end, if the variable’s value is ‘True’, the element is appended to the empty list.

• This is the output that is displayed on the console.