Python program to calculate Date, Month and Year from Seconds

Generally, time is given in hours or minutes or seconds and from the given seconds, we can calculate the number of days, months and years. There are different modules and functions available in python such as datetime, time and divmod() which helps us to calculate the date month and year from seconds.

Using Datatime module

Datetime module offers classes to manipulate the dates and times. This module provides various functions and methods such as date, time, datetime, timedelta, minyear, maxyear, UTC etc.

In the datetime method of datetime module we have the function utcfromtimestamp() which takes the seconds as the input argument and converts the seconds into year, date and month.

Syntax

The syntax for using the utcfromtimestamp() function is as follows.

 datetime.datetime.utcfromtimestamp(seconds) 

Example

In this example we are passing the number of seconds as 1706472809 to the utcfromtimestamp() of the datetime module then returns the year as 2024, date as 28 and month as 1.

 import datetime def calculate_date(seconds): date = datetime.datetime.utcfromtimestamp(seconds) year = date.year month = date.month day = date.day return day, month, year seconds = 1706472809 day, month, year = calculate_date(seconds) print("The day, month and year from the given seconds:",day, month, year) 

Output

 The day, month and year from the given seconds: 28 1 2024 

Using time module

The time module provides various time related functions such as asctime, cloc_gettime and gmtime etc.

The gmtime() function takes the seconds as the input argument and converts the seconds to a tuple and extract the year, day and month.

Syntax

The following is the syntax for using the time.gmtime() function.

 time.gmtime(seconds) 

Example

Here in this example we are going to pass the number seconds as the input argument to the gmtime() function of the time module then it returns the conversion of year, day and month.

 import time def calculate_date(seconds): time_tuple = time.gmtime(seconds) day = time_tuple.tm_mday month = time_tuple.tm_mon year = time_tuple.tm_year return day, month, year seconds = 1706472809 day, month, year = calculate_date(seconds) print("The day, month and year from the given seconds:",day, month, year) 

Output

 The day, month and year from the given seconds: 28 1 2024 

Using the divmod() function

The divmod() function takes any two real numbers as the input arguments and returns the tuple with quotient and remainder of the given numbers.

Syntax

The below is the syntax for divmod() function.

 quotient,remainder = divmod(val1,val2) 

Example

In this example we are creating a function with the name calculate_name which takes seconds as the input argument. In the function we use the divmod() function. The year starts from 1970 so we have to check if the year is leap year or not and generate the days and months. Next it returns the day, month and year as the output.

 def calculate_date(seconds): minutes, seconds = divmod(seconds, 60) hours, minutes = divmod(minutes, 60) days, hours = divmod(hours, 24) year = 1970 while days > 365: if year % 4 == 0 and (year % 100 != 0 or year % 400 == 0): if days > 366: days -= 366 year += 1 else: break else: days -= 365 year += 1 month_days = [31, 28 + (year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)), 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] month = 1 while days >= month_days[month - 1]: days -= month_days[month - 1] month += 1 return days + 1, month, year seconds = 1706472809 day, month, year = calculate_date(seconds) print(day, month, year) 

Output

 28 1 2024