Python Pandas - Return a new Index with elements of index not in other but unsort the result

To return a new Index with elements of index not in other but unsort the result, use the difference() method. Set the sort parameter to False.

At first, import the required libraries −

import pandas as pd

Creating two Pandas index −

index1 = pd.Index([30, 10, 20, 50, 40]) index2 = pd.Index([80, 40, 60, 20, 55])

Display the Pandas index1 and index2 −

print("Pandas Index1...\n",index1) print("Pandas Index2...\n",index2)

Get the difference of both the indexes. Results are unsorted using the "sort" parameter with value "False" −

res = index1.difference(index2, sort=False) 

Example

Following is the code −

import pandas as pd # Creating two Pandas index index1 = pd.Index([30, 10, 20, 50, 40]) index2 = pd.Index([80, 40, 60, 20, 55]) # Display the Pandas index1 and index2 print("Pandas Index1...\n",index1) print("Pandas Index2...\n",index2) # Return the number of elements in Index1 and Index2 print("\nNumber of elements in index1...\n",index1.size) print("\nNumber of elements in index2...\n",index2.size) # Get the difference of both the indexes # Results are unsorted using the "sort" parameter with value "False" res = index1.difference(index2, sort=False) # Difference of both the indexes i.e. return a new Index with elements of index not in other print("\nDifference...\n",res)

Output

This will produce the following output −

Pandas Index1... Int64Index([30, 10, 20, 50, 40], dtype='int64') Pandas Index2... Int64Index([80, 40, 60, 20, 55], dtype='int64') Number of elements in index1... 5 Number of elements in index2... 5 Difference... Int64Index([30, 10, 50], dtype='int64')