Print the string after the specified character has occurred given no. of times in C Program

Task is to print the given after the specified character occurrence for given number of times which is specified by the user

Input : string = {“I am harsh vaid “}    Char =’a’    Count =2 Output : rsh vaid

It means user specified character ‘a’ and its occurrence 2 so the output string should be displayed after two occurrences of a.

Algorithm

START Step 1 -> input character in ch(e.g. ‘a’) and count(e.g. 2) as int Step 2 -> declare and initialize n with size of a string by sizeof(string)/sizeof(string[0]) Step 3 - > Loop For i to 0 and i<n and i++    IF count > 0       IF string[i]==ch          Count=count-1       End IF       Continue    End IF    Else       Print string[i]    End Else Step 4 -> End For STOP

Example

#include <stdio.h> int main(int argc, char const *argv[]) {    char string[] = {"I am Harsh Vaid"};    char ch = 'a';    int i, count = 2;    int n = sizeof(string)/sizeof(string[0]);    for( i = 0; i < n; i++ ) {       if(count>0) {          if(string[i]==ch) {             count--;          }          continue;       }       else       printf("%c", string[i]);    }    return 0; }

Output

If we run above program then it will generate following output

rsh Vaid