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Populate Inorder Successor for all nodes in C++
In this problem, we are given a tree. The structure contains a pointer next. Our task is to populate this pointer with the inorder successor of the node.
struct node {    int value;    struct node* left;    struct node* right;    struct node* next; } All the next pointer are set to NULL and we have to set the pointer to the inorder successor of the node.
Inorder traversal − This traverses in the following form,
Left node -> root Node -> right node.
Inorder successor − the inorder successor is the node that comes after the current node is the inorder traversal of the tree.
Let’s take an example to understand the problem,

The in-order traversal is 7 8 3 5 9 1
Populating each node −
Next of 5 is 9 Next of 8 is 3 Next of 7 is 8 Next of 3 is 5 Next of 9 is 1
To solve this problem, we will traverse the tree but in a reverse in the order form. Then we will put the last visit element to the next of the number.
Example
Program to show the implementation of our solution,
#include<iostream> using namespace std; struct node {    int data;    node *left;    node *right;    node *next; }; node* insertNode(int data){    node* Node = new node();    Node->data = data;    Node->left = NULL;    Node->right = NULL;    Node->next = NULL;    return(Node); } void populateTree(node* pop){    static node *next = NULL;    if (pop){       populateTree(pop->right);       pop->next = next;       next = pop;       populateTree(pop->left);    } } void printNext(node * root) {    node *ptr = root->left->left;    while(ptr){       cout<<"Next of "<<ptr->data<<" is ";       cout<<(ptr->next? ptr->next->data: -1)<<endl;       ptr = ptr->next;    } } int main() {    node *root = insertNode(15);    root->left = insertNode(99);    root->right = insertNode(1);    root->left->left = insertNode(76);    root->left->right = insertNode(31);    cout<<"Populating the Tree by adding inorder successor to the next\n";    populateTree(root);    printNext(root);    return 0; }  Output
Populating the Tree by adding inorder successor to the next
Next of 76 is 99 Next of 99 is 31 Next of 31 is 15 Next of 15 is 1 Next of 1 is -1
