MySQL query to return the count of only NO values from corresponding column value

Let us first create a table −

mysql> create table DemoTable1829      (      Name varchar(20),      isTopper ENUM('YES','NO')      ); Query OK, 0 rows affected (0.00 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable1829 values('Chris','yes'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1829 values('David','yes'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1829 values('Mike','no'); Query OK, 1 row affected (0.00 sec) mysql> insert into DemoTable1829 values('David','yes'); Query OK, 1 row affected (0.00 sec)

Display all records from the table using select statement −

mysql> select * from DemoTable1829;

This will produce the following output −

+-------+----------+ | Name  | isTopper | +-------+----------+ | Chris | YES      | | David | YES      | | Mike  | NO   | | David | YES      | +-------+----------+ 4 rows in set (0.00 sec)

Here is the query to return the count of only NO values −

mysql> select Name,sum(isTopper='no')      from DemoTable1829      group by Name;

This will produce the following output −

+-------+--------------------+ | Name  | sum(isTopper='no') | +-------+--------------------+ | Chris |                  0 | | David |                  0 | | Mike  |                  1 | +-------+--------------------+ 3 rows in set (0.00 sec)