MySQL query to display only the records that contains single word?



For this, you can filter records on the basis of LIKE. Let us first create a table −

mysql> create table DemoTable (    Name varchar(50) ); Query OK, 0 rows affected (0.50 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable values('John Smith'); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable values('John'); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable values('Adam Smith'); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable values('Carol'); Query OK, 1 row affected (0.10 sec) mysql> insert into DemoTable values('David Miller'); Query OK, 1 row affected (0.10 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

This will produce the following output −

+--------------+ | Name | +--------------+ | John Smith | | John | | Adam Smith | | Carol | | David Miller | +--------------+ 5 rows in set (0.00 sec)

Following is the query to display records containing a single word. NOT LIKE is used here to exclude records with more than one word i.e. NOT LIKE '% %' −

mysql> select *from DemoTable where Name not like '% %';

This will produce the following output −

+-------+ | Name | +-------+ | John | | Carol | +-------+ 2 rows in set (0.00 sec)
Updated on: 2019-10-04T07:15:37+05:30

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