Multiply a Legendre series by an independent variable in Python

To multiply the Legendre series c by x, where x is the independent variable, use the polynomial.laguerre.legmulx() method in Python Numpy. The method returns an array representing the result of the multiplication. Returns the difference of two Legendre series c1 - c2. The arguments are sequences of coefficients ordered from lowest order term to highest, i.e., [1,2,3] represents the series P_0 + 2*P_1 + 3*P_2. The parameter, c is a 1-D array of Legendre series coefficients ordered from low to high.

Steps

At first, import the required library −

import numpy as np from numpy.polynomial import laguerre as L

Create an array −

c = np.array([1, 2, 3])

Display the array −

print("Our Array...\n",c)

Check the Dimensions −

print("\nDimensions of our Array...\n",c.ndim)

Get the Datatype −

print("\nDatatype of our Array object...\n",c.dtype)

Get the Shape −

print("\nShape of our Array object...\n",c.shape)

To multiply the Legendre series c by x, where x is the independent variable, use the polynomial.laguerre.legmulx() method in Python Numpy −

print("\nResult....\n",L.legmulx(c))

Example

import numpy as np from numpy.polynomial import legendre as L # Create an array c = np.array([1, 2, 3]) # Display the array print("Our Array...\n",c) # Check the Dimensions print("\nDimensions of our Array...\n",c.ndim) # Get the Datatype print("\nDatatype of our Array object...\n",c.dtype) # Get the Shape print("\nShape of our Array object...\n",c.shape) # To multiply the Legendre series c by x, where x is the independent variable, use the polynomial.laguerre.legmulx() method in Python Numpy print("\nResult....\n",L.legmulx(c))

Output

Our Array...    [1 2 3] Dimensions of our Array... 1 Datatype of our Array object... int64 Shape of our Array object... (3,) Result....    [0.66666667 2.2 1.33333333 1.8 ]