Missing even and odd elements from the given arrays in C++

Problem statement

Given two integer arrays even [] and odd [] which contains consecutive even and odd elements respectively with one element missing from each of the arrays. The task is to find the missing elements.

Example

If even[] = {10, 8, 6, 16, 12} and odd[] = {3, 9, 13, 7, 11} then missing number from even array is 14 and from odd array is 5.

Algorithm

• Store the minimum and the maximum even elements from the even[] array in variables minEven and maxEven
• Sum of first N even numbers is N * (N + 1). Calculate sum of even numbers from 2 to minEven say sum1 and sum of even numbers from 2 to maxEven say sum2
• The required sum of the even array will be reqSum = sum2 – sum1 + minEven, subtracting the even[] array sum from this reqSum will give us the missing even number
• Similarly, the missing odd number can also be found as we know that the sum of first N odd numbers is N2

Example

 Live Demo

#include <bits/stdc++.h> using namespace std; void findMissingNums(int even[], int sizeEven, int odd[], int sizeOdd) {    int minEven = INT_MAX;    int maxEven = INT_MIN;    int minOdd = INT_MAX;    int maxOdd = INT_MIN;    int sumEvenArr = 0, sumOddArr = 0;    for (int i = 0; i < sizeEven; i++) {       minEven = min(minEven, even[i]);       maxEven = max(maxEven, even[i]);       sumEvenArr += even[i];    }    for (int i = 0; i < sizeOdd; i++) {       minOdd = min(minOdd, odd[i]);       maxOdd = max(maxOdd, odd[i]);       sumOddArr += odd[i];    }    int totalTerms = 0, reqSum = 0;    totalTerms = minEven / 2;    int evenSumMin = totalTerms * (totalTerms + 1);    totalTerms = maxEven / 2;    int evenSumMax = totalTerms * (totalTerms + 1);    reqSum = evenSumMax - evenSumMin + minEven;    cout << "Missing even number = " << reqSum - sumEvenArr << "\n";    totalTerms = (minOdd / 2) + 1;    int oddSumMin = totalTerms * totalTerms;    totalTerms = (maxOdd / 2) + 1;    int oddSumMax = totalTerms * totalTerms;    reqSum = oddSumMax - oddSumMin + minOdd;    cout << "Missing odd number = " << reqSum - sumOddArr << "\n"; } int main() {    int even[] = {10, 8, 6, 16, 12};    int sizeEven = sizeof(even) / sizeof(even[0]);    int odd[] = {3, 9, 13, 7, 11};    int sizeOdd = sizeof(odd) / sizeof(odd[0]);    findMissingNums(even, sizeEven, odd, sizeOdd);    return 0; }

When you compile and execute above program. It generates following output −

Output

Missing even number = 14 Missing odd number = 5