Largest Even and Odd N-digit numbers in C++

In this tutorial, we are going to write a program that finds the largest even and odd number of n digits number.

Let's see the steps to solve the problem.

• Initialise the number n.
• The largest odd number is pow(10, n) - 1.
• The largest even number is odd - 1.

Example

Let's see the code.

 Live Demo

#include <bits/stdc++.h> using namespace std; void findEvenAndOddNumbers(int n) {    int odd = pow(10, n) - 1;    int even = odd - 1;    cout << "Even: " << even << endl;    cout << "Odd: " << odd << endl; } int main() {    int n = 6;    findEvenAndOddNumbers(n);    return 0; }

Output

If you run the above code, then you will get the following result.

Even: 999998 Odd: 999999

Conclusion

If you have any queries in the tutorial, mention them in the comment section.