JavaScript array: Find all elements that appear more than n times



We have an array of Number/String literals that contains some repeated entries. Our job is to write a function that takes in a positive integer Number n and returns a subarray of all the elements that makes appearance more than or equal to the number n specified by the only argument.

Therefore, let's write the code for this function −

We will use a Map() to keep count of the frequency of elements and later return the elements that exceed the specified count. The code for this will be −

Example

const arr = [34, 6, 34, 8, 54, 7, 87, 23, 34, 6, 21, 6, 23, 4, 23]; const moreThan = (arr, num) => {    const creds = arr.reduce((acc, val) => {       let { map, res } = acc;       const count = map.get(val);       if(!count && typeof count !== 'number'){          map.set(val, 1);       }else if(num - count <= 1){          res.push(val);       } else {          map.set(val, count+1);       };       return {map, res};    }, {       map: new Map(),       res: []    });    return creds.res; }; console.log(moreThan(arr, 3));

Output

The output in the console will be −

[34, 6, 23]
Updated on: 2020-08-31T06:44:32+05:30

405 Views

Kickstart Your Career

Get certified by completing the course

Get Started
Advertisements