Java Program to sort an array in case-sensitive order

An array can be sorted in case-sensitive order using the java.util.Arrays.sort() method. Only a single argument required in this case for this method i.e. the array to be sorted. A program that demonstrates this is given as follows −

Example

 Live Demo

import java.util.Arrays; public class Demo {    public static void main(String args[]) {       String[] arr = new String[] { "apple", "mango", "Banana", "Melon", "orange" };       System.out.print("The unsorted array is: ");       System.out.println(Arrays.toString(arr));       Arrays.sort(arr);       System.out.print("The sorted array in case-sensitive order is: ");       System.out.println(Arrays.toString(arr));    } }

Output

The unsorted array is: [apple, mango, Banana, Melon, orange] The sorted array in case-sensitive order is: [Banana, Melon, apple, mango, orange]

Now let us understand the above program.

First the array arr[] is defined. Then the unsorted array is printed. A code snippet which demonstrates this is as follows −

String[] arr = new String[] { "apple", "mango", "Banana", "Melon", "orange" }; System.out.print("The unsorted array is: "); System.out.println(Arrays.toString(arr));

The Arrays.sort() method is used to sort the array in case-sensitive order. Then the sorted array is displayed. A code snippet which demonstrates this is as follows −

Arrays.sort(arr); System.out.print("The sorted array in case-sensitive order is: "); System.out.println(Arrays.toString(arr));