How we can perform sort on ObjectId column in MongoDB?

To perform sort on ObjectId column, use sort(). Let us create a collection with document.

> db.demo403.insertOne({"Name":"Chris"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e6f89b0fac4d418a017858e") } > db.demo403.insertOne({"Name":"David"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e6f89b2fac4d418a017858f") } > db.demo403.insertOne({"Name":"Bob"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e6f89b5fac4d418a0178590") } > db.demo403.insertOne({"Name":"Adam"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e6f89b8fac4d418a0178591") }

Display all documents from a collection with the help of find() method −

> db.demo403.find();

This will produce the following output −

{ "_id" : ObjectId("5e6f89b0fac4d418a017858e"), "Name" : "Chris" } { "_id" : ObjectId("5e6f89b2fac4d418a017858f"), "Name" : "David" } { "_id" : ObjectId("5e6f89b5fac4d418a0178590"), "Name" : "Bob" } { "_id" : ObjectId("5e6f89b8fac4d418a0178591"), "Name" : "Adam" }

Following is the query to perform sort on ObjectId column in MongoDB −

> db.demo403.find().sort({_id:-1});

This will produce the following output −

{ "_id" : ObjectId("5e6f89b8fac4d418a0178591"), "Name" : "Adam" } { "_id" : ObjectId("5e6f89b5fac4d418a0178590"), "Name" : "Bob" } { "_id" : ObjectId("5e6f89b2fac4d418a017858f"), "Name" : "David" } { "_id" : ObjectId("5e6f89b0fac4d418a017858e"), "Name" : "Chris" }