How to select record except the lower value record against a specific value in MySQL?

For this, you need to use the WHERE clause. Following is the syntax −

select *from yourTableName where yourColumnName > yourValue;

Let us create a table −

mysql> create table demo27 −> ( −> id int not null auto_increment primary key, −> value int −> ); Query OK, 0 rows affected (3.14 sec)

Insert some records into the table with the help of insert command −

mysql> insert into demo27(value) values(50); Query OK, 1 row affected (0.12 sec) mysql> insert into demo27(value) values(500); Query OK, 1 row affected (0.20 sec) mysql> insert into demo27(value) values(100); Query OK, 1 row affected (0.17 sec) mysql> insert into demo27(value) values(400); Query OK, 1 row affected (0.14 sec) mysql> insert into demo27(value) values(100); Query OK, 1 row affected (0.11 sec) mysql> insert into demo27(value) values(800); Query OK, 1 row affected (0.10 sec) mysql> insert into demo27(value) values(600); Query OK, 1 row affected (0.15 sec)

Display records from the table using select statement −

mysql> select *from demo27;

This will produce the following output −

+----+-------+ | id | value | +----+-------+ | 1 | 50 | | 2 | 500 | | 3 | 100 | | 4 | 400 | | 5 | 100 | | 6 | 800 | | 7 | 600 | +----+-------+ 7 rows in set (0.00 sec)

Following is the query to select record except the lower value record against a value in MySQL −

mysql> select *from demo27 where value > 500;

This will produce the following output −

+----+-------+ | id | value | +----+-------+ | 6 | 800 | | 7 | 600 | +----+-------+ 2 rows in set (0.00 sec)