How to return the position of a document relative to the collection in MongoDB?



To return the position of a document relative to the collection, use sort() along with count(). Let us create a collection with documents −

> db.demo47.insertOne({"ClientName":"Adam"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e267240cfb11e5c34d898f0") } > db.demo47.insertOne({"ClientName":"John"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e267243cfb11e5c34d898f1") } > db.demo47.insertOne({"ClientName":"Chris"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e267247cfb11e5c34d898f2") } > db.demo47.insertOne({"ClientName":"Sam"}); {    "acknowledged" : true,    "insertedId" : ObjectId("5e26724ccfb11e5c34d898f3") }

Display all documents from a collection with the help of find() method −

> db.demo47.find();

This will produce the following output −

{ "_id" : ObjectId("5e267240cfb11e5c34d898f0"), "ClientName" : "Adam" } { "_id" : ObjectId("5e267243cfb11e5c34d898f1"), "ClientName" : "John" } { "_id" : ObjectId("5e267247cfb11e5c34d898f2"), "ClientName" : "Chris" } { "_id" : ObjectId("5e26724ccfb11e5c34d898f3"), "ClientName" : "Sam" }

Following is the query to return the position of a document relative to the collection in MongoDB −

> db.demo47.find({ClientName: {$lt: "John"}}).sort({ClientName: 1}).count();

This will produce the following output −

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Updated on: 2020-04-03T12:24:16+05:30

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