How to match non-word boundaries using Java RegEx?

You can match the non-word boundaries using the meta character “\B”.

Example 1

import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Example {    public static void main(String args[]) {       //Reading String from user       System.out.println("Enter a String");       Scanner sc = new Scanner(System.in);       String input = sc.nextLine();       String regex = "\B";       //Compiling the regular expression       Pattern pattern = Pattern.compile(regex);       //Retrieving the matcher object       Matcher matcher = pattern.matcher(input);       int count = 0;       while(matcher.find()) {          count++;       }       System.out.println("Number of non-word boundaries: "+count);    } }

Output

Enter a String this is a sample text Number of non-word boundaries: 12

Example 2

import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Example {    public static void main( String args[] ) {       String regex = "\Bin";       Scanner sc = new Scanner(System.in);       System.out.println("Enter a string: ");       String input = sc.nextLine();       Pattern p = Pattern.compile(regex);       Matcher m = p.matcher(input);       int count = 0;       while(m.find()) {          count++;       }       System.out.println("no of non-word boundaries: "+count);    } }

Output

Enter a string: this is a sample text in win tin pin sin no of non-word boundaries: 4