How to create a column of factorial values in data frames stored in R list?

To create a column of factorial values in data frames stored in R list, we can follow the below steps −

• First of all, create a list of data frames.

• Then, use lapply function to create a column of factorial values in data frames stored in the list.

Example

Create the list of data frames

Using data.frame function to create data frames and list function to create the list of those data frames −

df1<-data.frame(x=sample(1:9,25,replace=TRUE)) df2<-data.frame(x=sample(1:9,25,replace=TRUE)) List<-list(df1,df2) List

Output

On executing, the above script generates the below output(this output will vary on your system due to randomization) −

[[1]] x 1 1 2 2 3 8 4 9 5 7 6 1 7 8 8 8 9 6 10 7 11 2 12 9 13 2 14 8 15 8 16 4 17 5 18 1 19 6 20 3 21 8 22 3 23 4 24 6 25 3 [[2]] x 1 9 2 1 3 8 4 8 5 9 6 9 7 6 8 2 9 3 10 8 11 4 12 4 13 6 14 6 15 9 16 7 17 4 18 2 19 6 20 1 21 2 22 1 23 7 24 1 25 4

Create a column of factorial values

Using lapply function to create a column of factorial values in data frames df1 and df2 stored in the list called List as shown below −

df1<-data.frame(x=sample(1:9,25,replace=TRUE)) df2<-data.frame(x=sample(1:9,25,replace=TRUE)) List<-list(df1,df2) lapply(List,function(x) { + x$Factorial<-factorial(x$x) + return(x) + })

Output

[[1]] x Factorial 1 6 720 2 4 24 3 5 120 4 3 6 5 9 362880 6 1 1 7 5 120 8 8 40320 9 6 720 10 5 120 11 3 6 12 9 362880 13 9 362880 14 1 1 15 6 720 16 4 24 17 8 40320 18 3 6 19 2 2 20 9 362880 21 8 40320 22 3 6 23 3 6 24 2 2 25 6 720 [[2]] x Factorial 1 8 40320 2 5 120 3 1 1 4 4 24 5 1 1 6 4 24 7 9 362880 8 7 5040 9 7 5040 10 5 120 11 2 2 12 4 24 13 8 40320 14 4 24 15 3 6 16 8 40320 17 7 5040 18 8 40320 19 1 1 20 4 24 21 9 362880 22 8 40320 23 2 2 24 4 24 25 6 720