How can I sort documents in MongoDB 4 and display only a single field?

To sort documents in MongoDB 4, use sort(). To show only a single field, which is sorted, set it to 1.

Let us create a collection with documents −

> db.demo611.insertOne({"Name":"Chris"});{    "acknowledged" : true, "insertedId" : ObjectId("5e987110f6b89257f5584d83") } > db.demo611.insertOne({"Name":"Adam"});{    "acknowledged" : true, "insertedId" : ObjectId("5e987115f6b89257f5584d84") } > db.demo611.insertOne({"Name":"John"});{    "acknowledged" : true, "insertedId" : ObjectId("5e987118f6b89257f5584d85") } > db.demo611.insertOne({"Name":"Bob"});{    "acknowledged" : true, "insertedId" : ObjectId("5e98711bf6b89257f5584d86") }

Display all documents from a collection with the help of find() method −

> db.demo611.find(); This will produce the following output: { "_id" : ObjectId("5e987110f6b89257f5584d83"), "Name" : "Chris" } { "_id" : ObjectId("5e987115f6b89257f5584d84"), "Name" : "Adam" } { "_id" : ObjectId("5e987118f6b89257f5584d85"), "Name" : "John" } { "_id" : ObjectId("5e98711bf6b89257f5584d86"), "Name" : "Bob" }

Following is the query to sort documents using MongoDB 4 −

> db.demo611.find().sort({Name:1});

This will produce the following output &mius;

{ "_id" : ObjectId("5e987115f6b89257f5584d84"), "Name" : "Adam" } { "_id" : ObjectId("5e98711bf6b89257f5584d86"), "Name" : "Bob" } { "_id" : ObjectId("5e987110f6b89257f5584d83"), "Name" : "Chris" } { "_id" : ObjectId("5e987118f6b89257f5584d85"), "Name" : "John" }