How can I select rows which fall on a specific day of week in MySQL?

For specific day of week, use DAYOFWEEK().

Let us first create a table −

mysql> create table DemoTable785 ( CustomerId int NOT NULL AUTO_INCREMENT PRIMARY KEY, CustomerName varchar(100), ShoppingDate date ); Query OK, 0 rows affected (0.61 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Chris','2019-07-03'); Query OK, 1 row affected (0.20 sec) mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Robert','2019-07-01'); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('David','2019-07-06'); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Carol','2019-07-19'); Query OK, 1 row affected (0.19 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable785;

This will produce the following output -

+------------+--------------+--------------+ | CustomerId | CustomerName | ShoppingDate | +------------+--------------+--------------+ | 1          | Chris        | 2019-07-03 | | 2          | Robert       | 2019-07-01 | | 3          | David        | 2019-07-06 | | 4          | Carol       | 2019-07-19 | +------------+--------------+--------------+ 4 rows in set (0.00 sec)

Following is the query to select rows which fall on a specific day of week −

mysql> select *from DemoTable785 where DAYOFWEEK(ShoppingDate)=2;

This will produce the following output -

+------------+--------------+--------------+ | CustomerId | CustomerName | ShoppingDate | +------------+--------------+--------------+ | 2 | Robert | 2019-07-01 | +------------+--------------+--------------+ 1 row in set (0.00 sec)