Get the unqualified name of a class in Java



A qualified class name in Java contains the package that the class originated from. In contrast to this, the unqualified class name contains only the class name without any package information. 

A program that gets the unqualified name of a class is given as follows:

Example

 Live Demo

public class Demo {    public static void main(String[] argv) throws Exception {       Class c = java.util.ArrayList.class;       String className = c.getName();       System.out.println("The qualified class name is: " + className);       if (className.lastIndexOf('.') < 0) {          className = className.substring(className.lastIndexOf('.') + 1);          className = className.replace('$', '.');       }       System.out.println("The unqualified class name is: " + className);    } }

Output

The qualified class name is: java.util.ArrayList The unqualified class name is: ArrayList

Now let us understand the above program.

First the qualified class name is displayed using the getName() method. A code snippet which demonstrates this is as follows −

Class c = java.util.ArrayList.class; String className = c.getName(); System.out.println("The qualified class name is: " + className);

The unqualified class name is obtained using the substring() method that provides the substring of the className from the last index of ‘.’ Then the unqualified class name is displayed. A code snippet which demonstrates this is as follows −

if (className.lastIndexOf('.') < 0) {    className = className.substring(className.lastIndexOf('.') + 1);    className = className.replace('$', '.'); } System.out.println("The unqualified class name is: " + className);
Updated on: 2020-06-25T13:49:24+05:30

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