Get the element ordered first in Java TreeSet

To get the element ordered first i.e. the first element in TreeSet, use the first() method.

Create a TreeSet and add elements to it −

TreeSet<String> set = new TreeSet<String>(); set.add("65"); set.add("45"); set.add("19"); set.add("27"); set.add("89"); set.add("57");

Now, get the first element −

set.first()

The following is an example to get the element ordered first in TreeSet −

Example

 Live Demo

import java.util.*; public class Demo { public static void main(String args[]) { TreeSet<String> set = new TreeSet<String>(); set.add("65"); set.add("45"); set.add("19"); set.add("27"); set.add("89"); set.add("57"); System.out.println("TreeSet elements (Sorted)..."); Iterator<String> i = set.iterator(); while(i.hasNext()) { System.out.println(i.next()); } System.out.println("Element order first = "+set.first()); } }

Output

TreeSet elements (Sorted)... 19 27 45 57 65 89 Element ordered first = 19