Finding next n leap years in JavaScript

We are required to write a function that takes a positive integer n and returns an array of next n leap years. We will break this problem into three parts −

Part 1: Finding current year via JS

The code to find current year via JS will be −

// getting the current year from a new instance of Date object const year = new Date().getFullYear();

Part 2: Checking for leap year

We will now write a function isLeap() that takes in a number and returns a boolean based on the number being a leap year or not.

A year is considered as a leap year if atleast one of these two conditions are met −

• It is multiple of 400.
• It is multiple of 4 and not multiple of 100.

Keeping these things in mind let’s write the function isLeap() −

// function to check for a leap year const isLeap = year => {    return year % 400 === 0 || (year % 4 === 0 && year % 100 !== 0); };

Part 3: Finding next n leap years

Example

// function to check for a leap year const isLeap = year => {    return year % 400 === 0 || (year % 4 === 0 && year % 100 !== 0); }; const nextNLeap = n => {    const arr = [];    let year = new Date().getFullYear()+1;    while(arr.length < n){       if(isLeap(year++)){          arr.push(year-1);       };    };    return arr; }; console.log(nextNLeap(5)); console.log(nextNLeap(25));

Output

The output in the console will be −

[ 2024, 2028, 2032, 2036, 2040 ] [    2024, 2028, 2032, 2036, 2040,    2044, 2048, 2052, 2056, 2060,    2064, 2068, 2072, 2076, 2080,    2084, 2088, 2092, 2096, 2104,    2108, 2112, 2116, 2120, 2124 ]