Find missing numbers in a sorted list range in Python

Given a list with sorted numbers, we want to find out which numbers are missing from the given range of numbers.

With range

we can design a for loop to check for the range of numbers and use an if condition with the not in operator to check for the missing elements.

Example

 Live Demo

listA = [1,5,6, 7,11,14] # Original list print("Given list : ",listA) # using range res = [x for x in range(listA[0], listA[-1]+1)                               if x not in listA] # Result print("Missing elements from the list : \n" ,res)

Output

Running the above code gives us the following result −

Given list : [1, 5, 6, 7, 11, 14] Missing elements from the list : [2, 3, 4, 8, 9, 10, 12, 13]

with ZIP

The ZIP function

Example

 Live Demo

listA = [1,5,6, 7,11,14] # printing original list print("Given list : ",listA) # using zip res = [] for m,n in zip(listA,listA[1:]):    if n - m > 1:       for i in range(m+1,n):          res.append(i) # Result print("Missing elements from the list : \n" ,res)

Output

Running the above code gives us the following result −

Given list : [1, 5, 6, 7, 11, 14] Missing elements from the list : [2, 3, 4, 8, 9, 10, 12, 13]