Find duplicates under given constraints in C++



Suppose we have a list with 6 different numbers. Only one number is repeated five times. So there are total 10 elements in the array. Find duplicate numbers using only two comparisons. If the list is like [1, 2, 3, 4, 4, 4, 4, 4, 5, 6], so output is 4.

As there are only 10 numbers, then for any type of duplicate numbers, the range of numbers will be placed from index 3 to 5. By checking these indices, we can find the result.

Example

#include<iostream> using namespace std; int getDuplicate(int array[]) {    if (array[3] == array[4])       return array[3];    else if (array[4] == array[5])       return array[4];    else       return array[5]; } int main() {    int a[] = {1, 2, 3, 4, 4, 4, 4, 4, 5, 6};    cout << "Duplicate element: " << getDuplicate(a); }

Output

Duplicate element: 4
Updated on: 2019-11-01T07:13:57+05:30

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