Find average on the basis of corresponding duplicate VARCHAR values in MySQL

Let us first create a table −

mysql> create table DemoTable(    Value int,    Value2 varchar(100) ); Query OK, 0 rows affected (0.84 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable values(10,'999.999.999.999'); Query OK, 1 row affected (0.18 sec) mysql> insert into DemoTable values(20,'888.888.888.888'); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable values(30,'999.999.999.999'); Query OK, 1 row affected (0.09 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

This will produce the following output −

+-------+-----------------+ | Value | Value2 | +-------+-----------------+ | 10 | 999.999.999.999 | | 20 | 888.888.888.888 | | 30 | 999.999.999.999 | +-------+-----------------+ 3 rows in set (0.00 sec)

Here is the query to find average on the basis of corresponding VARCHAR records::

mysql> select Value2,avg(Value) from DemoTable group by Value2;

This will produce the following output −

+-----------------+------------+ | Value2 | avg(Value) | +-----------------+------------+ | 999.999.999.999 | 20.0000 | | 888.888.888.888 | 20.0000 | +-----------------+------------+ 2 rows in set (0.06 sec)