C++ chrono::count() Function

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The std::chrono::count() function in C++, provides facilitates for date and time manipulation. It is typically used with chrono::duration objects to retrieve the numerical values representing the tine span in specific units, like seconds or milliseconds.

This function helps to convert the chrono::duration instances into fundamental types (such as int or double) for easy calculations or conversions.

Syntax

Following is the syntax for std::chrono::count() function.

 constexpr rep count() const; 

Parameters

This function does not accepts any parameters.

Return value

This function returns the number of ticks for this duration.

Example 1

In the following example, we are going to consider the basic usage of the count() function.

 #include <iostream> #include <chrono> int main() { std::chrono::seconds a(11); std::cout << "Result : " << a.count() << "s" << std::endl; return 0; } 

Output

Output of the above code is as follows −

 Result : 11s 

Example 2

Consider the following example, we are going to convert the minutes to seconds and using the count() function.

 #include <iostream> #include <chrono> int main() { std::chrono::minutes a(4); auto seconds = std::chrono::duration_cast < std::chrono::seconds > (a); std::cout << "Result : " << seconds.count() << "s" << std::endl; return 0; } 

Output

Following is the output of the above code −

 Result : 240s 

Example 3

Let's look at the following example, where we are going to convert the milliseconds to seconds and applying the count() function.

 #include <iostream> #include <chrono> int main() { std::chrono::milliseconds a(2000); std::cout << "Result : " << std::chrono::duration_cast < std::chrono::seconds > (a).count() << "s" << std::endl; return 0; } 

Output

If we run the above code it will generate the following output −

 Result : 2s