C++ code to find screen size with n pixels

Suppose we have a number n. In a display there will be n pixels. We have to find the size of rectangular display. The rule is like below −

• The number of rows (a) does not exceed number of columns (b) [a <= b]

• The difference between b - a is as minimum as possible

So, if the input is like n = 12, then the output will be (3, 4)

Steps

To solve this, we will follow these steps −

i := square root of n while n mod i is non-zero, do:    (decrease i by 1) return (i, n / i)

Example

Let us see the following implementation to get better understanding −

#include <bits/stdc++.h> using namespace std; void solve(int n){    int i = sqrt(n);    while (n % i)       i--;    cout << i << ", " << n / i; } int main(){    int n = 12;    solve(n); }

Input

12

Output

3, 4