Convert decimal fraction to binary number in C++

In this tutorial, we will be discussing a program to convert decimal fraction to a binary number.

For this we will be provided with a decimal fraction and integer ‘k’. Our task is to convert the given decimal fraction into its binary equivalent upto the given ‘k’ digits of decimal precision.

Example

 Live Demo

#include<bits/stdc++.h> using namespace std; //converting decimal to binary number string convert_tobinary(double num, int k_prec) {    string binary = "";    //getting the integer part    int Integral = num;    //getting the fractional part    double fractional = num - Integral;    //converting integer to binary    while (Integral) {       int rem = Integral % 2;       binary.push_back(rem +'0');       Integral /= 2;    }    //reversing the string to get the    //required binary number    reverse(binary.begin(),binary.end());    binary.push_back('.');    //converting fraction to binary    while (k_prec--) {       fractional *= 2;       int fract_bit = fractional;       if (fract_bit == 1) {          fractional -= fract_bit;          binary.push_back(1 + '0');       } else       binary.push_back(0 + '0');    }    return binary; } int main() {    double n = 4.47;    int k = 3;    cout << convert_tobinary(n, k) << "\n";    n = 6.986 , k = 5;    cout << convert_tobinary(n, k);    return 0; }

Output

100.011 110.11111