Check the number is Armstrong or not using C

Problem

How to check whether the given number is an Armstrong number or not using C Programming language?

Solution

Armstrong number is the number that is equal to the sum of cubes of its digits.

Syntax

pqrs………=pow(p,n)+pow(q,n)+pow(r,n)+……….

For example, 153,371,1634, etc., are Armstrong numbers.

153=1*1*1 + 5*5*5 + 3*3*3    =1+125+27    =153 (Armstrong number)

Program

 Live Demo

#include<stdio.h> int main(){    int number,remainder,total=0,temp;    printf("enter the number=");    scanf("%d",&number);    temp=number;    while(number>0){       remainder=number%10;       total=total+(remainder*remainder*remainder);       number=number/10;    }    if(temp==total)       printf("This number is Armstrong number");    else       printf("This number is not Armstrong number");    return 0; }

Output

enter the number=371 This number is Armstrong number Check: 371=3*3*3 +7*7*7 + 1*1*1            =27 + 343 +1            =371 enter the number=53 This number is not Armstrong number

Explanation

53 = 5*5*5 + 3*3*3    =125 +27    = 152 != 53