Caesar Cipher in Python

Suppose we have a lowercase alphabet string s, and an offset number say k. We have to replace every letter in s with a letter k positions further along the alphabet. We have to keep in mind that when the letter overflows past a or z, it gets wrapped around the other side.

So, if the input is like "hello", k = 3, then the output will be "khoor"

To solve this, we will follow these steps −

• Define a function shift(). This will take c

• i := ASCII of (c) - ASCII of ('a')

• i := i + k

• i := i mod 26

• return character from ASCII (ASCII of ('a') + i)

• From the main method, do the following −

• ret := for each character c in s, make a list of elements by calling shift(c)

• return ret

Let us see the following implementation to get better understanding −

Example

 Live Demo

class Solution:    def solve(self, s, k):       def shift(c):          i = ord(c) - ord('a')          i += k          i %= 26          return chr(ord('a') + i)       return "".join(map(shift, s)) ob = Solution() print(ob.solve("hello", 3))

Input

"hello", 3

Output

khoor