C Program to print all ASCII values.

Problem

Print the American Standard Code for Information Interchange (ASCII) values of 0 to 255 characters without initializing the character to integer type variable. Simply, use the format specifier.

Solution

Here we are writing a program to print only from 65 to 122.

If you want to see all ASCII values, in for loop you can write as follows −

For(i=0;i<255;i++)

Then, it prints all the ASCII values from 0 to 255.

The logic used to print the ASCII values from 65 to 122 is as follows −

Prints ASII values From A to z for (i = 65; i < =122; i++){    printf("%c \t\t %d
", i, i); }

Example

Following is the C program to print the ASCII values from 65 to 122 −

 Live Demo

#include <stdio.h> int main() {    // Declare Variables    int i = 0;    printf("Character \t ASCII Value

");    //Print ASCII Values    for (i = 65; i <=122; i++) {       printf("%c \t\t %d
", i, i);    }    return 0; }

Output

When the above program is executed, it produces the following output −

Character ASCII Value A 65 B 66 C 67 D 68 E 69 F 70 G 71 H 72 I 73 J 74 K 75 L 76 M 77 N 78 O 79 P 80 Q 81 R 82 S 83 T 84 U 85 V 86 W 87 X 88 Y 89 Z 90 [ 91 \ 92 ] 93 ^ 94 _ 95 ` 96 a 97 b 98 c 99 d 100 e 101 f 102 g 103 h 104 i 105 j 106 k 107 l 108 m 109 n 110 o 111 p 112 q 113 r 114 s 115 t 116 u 117 v 118 w 119 x 120 y 121 z 122