C program to add all perfect square elements in an array.

Problem

Write a program to find the sum of perfect square elements in an array.

Given a number of elements in array as input and the sum of all the perfect square of those elements present in the array is output.

Solution

For example,

Input= 1, 2, 3, 4, 5, 9,10,11,16 The perfect squares are 1, 4, 9, 16. Sum = 1 + 4 + 9 +16 = 30 Output: 30

Algorithm

Refer an algorithm given below to add the perfect square elements in an array.

Step 1 − Read number of elements in array at runtime.

Step 2 − Input the elements.

Step 3 − Declare and initialize the sum=0

Step 4 − Check, whether the array element is a perfect square or not.

Step 5 − If it is a perfect square, then, compute sum=sum+number.

Step 6 − Return sum.

Example

Following is the C program to find the sum of perfect square elements in an array −

#include<stdio.h> #include<math.h> int isPerfectSquare(int number){    int iVar;    float fVar;    fVar=sqrt((double)number);    iVar=fVar;    if(iVar==fVar)       return number;    else    return 0; } int main(){    int n;    printf("enter no: of elements:");    scanf("%d",&n);    int arr[n];    int i;    printf("enter the elements in an array:
");    for(i = 0; i < n; i++){       scanf("%d",&arr[i]);    }    int sum = 0;    for(i = 0; i < n; i++){       sum = sum + isPerfectSquare(arr[i]);    }    printf("sum=%d",sum);    return 0; }

Output

When the above program is executed, it produces the following output −

Run 1: enter no: of elements:5 enter the elements in an array: 1 3 5 9 10 sum=10 Run 2: enter no: of elements:5 enter the elements in an array: 1 4 9 16 25 sum=55