Write a C# function to print nth number in Fibonacci series?



Set the following, if the nth number is let’s say num −

int n = num- 1; int[] val = new int[n + 1];

Then set the default Fibonacci numbers on the first and second position −

val[0]= 0; val[1]= 1;

Loop through i=2 to i<=n and find the Fibonacci numbers −

for (int i = 2; i <= n;i++) {    val[i] = val[i - 2] + val[i - 1]; }

The following is the complete code −

Example

 Live Demo

using System; public class Demo {    public static void Main(string[] args) {       Demo g = new Demo();       int a = g.displayFibonacci(7);       Console.WriteLine(a);    }    public int displayFibonacci(int num) {       int n = num- 1;       int[] val = new int[n + 1];       val[0]= 0;       val[1]= 1;       for (int i = 2; i <= n;i++) {          val[i] = val[i - 2] + val[i - 1];       }       return val[n];    } }

Output

8
Updated on: 2020-06-20T14:25:20+05:30

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