When to use vararg methods in Java?

Whenever, you want to pass different number of arguments each time you call a method you should use vararg methods.

This example creates sumvarargs() method which takes variable no of int numbers as an argument and returns the sum of these arguments as an output.

Example

Live Demo

 public class Main { static int sumvarargs(int... intArrays) { int sum, i; sum = 0; for(i = 0; i< intArrays.length; i++) { sum += intArrays[i]; } return(sum); } public static void main(String args[]) { int sum = 0; sum = sumvarargs(new int[]{10,12,33}); System.out.println("The sum of the numbers is: " + sum); } } 

Output

 The sum of the numbers is: 55