Find the Sum of two Binary Numbers without using a method in C#?

First, declare and initialize two variables with the binary numbers.

val1 = 11010; val2 = 10100; Console.WriteLine("Binary one: " + val1); Console.WriteLine("Binary two: " + val2);

To get the sum, loop until both the value are 0.

while (val1 != 0 || val2 != 0) {    sum[i++] = (val1 % 10 + val2 % 10 + rem) % 2;    rem = (val1 % 10 + val2 % 10 + rem) / 2;    val1 = val1 / 10;    val2 = val2 / 10; }

Now, let us see the complete code to find the sum of two binary numbers.

Example

 Live Demo

using System; class Demo {    public static void Main(string[] args) {       long val1, val2;       long i = 0, rem = 0;       long[] sum = new long[30];           val1 = 11010;       val2 = 10100;       Console.WriteLine("Binary one: " + val1);       Console.WriteLine("Binary two: " + val2);       while (val1 != 0 || val2 != 0) {          sum[i++] = (val1 % 10 + val2 % 10 + rem) % 2;          rem = (val1 % 10 + val2 % 10 + rem) / 2;          val1 = val1 / 10;          val2 = val2 / 10;       }       if (rem != 0)       sum[i++] = rem;       i = i - 1;       Console.Write("Sum = ");       while (i >= 0)       Console.Write(sum[i--]);    } }

Output

Binary one: 11010 Binary two: 10100 Sum = 101110