Split a Circular List into 2 Halves17 Mar 2025 | 4 min read IntroductionA Circular linked list where the last node points back to the first node, forming a loop. Every node in the circular linked list has a data element and a pointer to the next node. In this article, we will be splitting a circular linked list into two halves, an operation in linked list manipulation where we will use Floyd's Cycle-finding algorithm. Key PointsNote: Each element in a circular linked list is called a node. A node consists of two parts: data and a pointer to the next node in the list.Circularity: The key characteristic of a circular linked list is that the last node's reference points back to the first node, creating a loop. This ensures that there is no real end to the list. Problem StatementWe have a circular linked list of length n. We have to split the original circular linked list into two halves Input Original Circular Linked List ![]() Output First Half ![]() Second Half ![]() Explantation The original number of nodes is 5, separated into 3 and 2 nodes. The given nodes are in odd numbers so that the first Half will contain the extra node than the second Half. AlgorithmTo split a circular linked list in C++ using Floyd's Cycle-Finding Algorithm (also known as the "Tortoise and Hare" algorithm), you can follow these steps:
Implementation C++Output: ![]() The above code uses Floyd's cycle-finding algorithm to find the midpoint of the circular linked list and then splits it into two halves. Note: As an example in this article, if the Inputs are in an odd number of nodes, the first Half will contain one Extra node.ConclusionIn conclusion, splitting a circular linked list into two halves we have used can be a useful operation when dealing with data manipulation and algorithms. We can divide the list into two equal parts by finding the middle node and breaking the circular reference. |
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