Node.js util.types.isSymbolObject() Method

In this article, we will discuss the Node.js util.types.isSymbolObject() method with its syntax, parameters, and several examples.

What is the Node.js util.types.isSymbolObject() method?

An internal Node.js API called util.types.isSymbolObject(), which is part of the util module and is mainly used to support internal Node.js APIs. It is employed to ascertain whether a given value belongs to a symbol object. The method returns true if the value is a symbol object; otherwise, it returns false. This technique is quite useful for internal Node.js APIs that work with symbol objects and require type verification.

Syntax:

It has the following syntax:

Parameters:

• util: It is the name of the built-in util module for Node.js.
• types: It is a feature of the util module, which has a number of utility types and functions.
• isSymbolObject(): It is the procedure for determining whether a given value represents a symbol object.
• value: The value we wish to verify is represented by this argument, which is supplied to the method.

Return value:

It returns a Boolean value, which means that it only returns true if the value is a symbol object and returns false otherwise.

Note: Calling Object() on a symbol primitive creates a symbol object.

Example 1:

Let us take an example to illustrate the Node.js util.types.isSymbolObject() method.

Output:

 false false true 

Explanation:

• This program checks whether or not provided objects are symbol objects using the util.types.isSymbolObject() method from the Node.js util package.
• It starts by creating a new Map object called 'm'. The reported Result accurately reflects the fact that Map objects are not symbol objects, as indicated by the response of false from util.types.isSymbolObject(m) when called.
• Using the Object() constructor, an object (o) is secondly generated. Moreover, the util.types.isSymbolObject(o) function returns false when invoked on this object because it is not a symbol object.
• Using the Symbol() constructor, a symbol object is finally constructed, and then the Object() constructor is used to transform it into an object. The util.types.isSymbolObject(s) method returns true as predicted since s is a symbol object when it is executed.

Example 2:

Let us take another example to illustrate the Node.js util.types.isSymbolObject() method.

Output:

 false false true 

Explanation:

• In this example, this code demonstrates how to use the util.types.isSymbolObject() function to determine whether different entities are symbol objects.
• In order to use its utility functions, the code first imports the util module as 'u' and then uses u.types. When a Map object is checked for whether it is a symbol object, the isSymbolObject() function returns false because objects inside a Map are not symbol objects.
• After that, the code uses the Symbol() constructor to generate a symbol called 's'. S is a symbol primitive, not an object; thus, when the u.types.isSymbolObject() function is used to determine if s is a symbol object, it returns false.
• Finally, the code uses the Object() constructor to convert the Symbol s into an object, symbolObj. The symbolObj is an object made from a symbol using the Object() constructor, making it a symbol object. Therefore, when types.isSymbolObject() is applied to symbolObj, it appropriately returns true.