Inorder predecessor and successor for a given key in BST6 Feb 2025 | 5 min read Introduction:Binary Search Trees (BSTs) are powerful data structures used extensively in computer science for efficient searching, insertion, and deletion operations. One common task when working with BSTs is finding the inorder predecessor and successor for a given key. Understanding Binary Search Trees (BSTs):Before diving into inorder predecessors and successors, let's briefly review what a BST is. A binary search tree is a binary tree where each node has at most two children, commonly referred to as the left child and the right child. The key property of a BST is that for any node, all nodes in its left subtree have keys less than its own key, and all nodes in its right subtree have keys greater than its own key. This property makes searching, insertion, and deletion operations efficient, typically with a time complexity of O(log n) for balanced trees. Inorder Traversal:Inorder traversal is a method of visiting all nodes of a binary tree in ascending order of their keys. In a BST, inorder traversal naturally gives us the elements in sorted order. The order of traversal is: left child, root, right child. Inorder Predecessor:The inorder predecessor of a node in a BST is the node with the largest key that is smaller than the key of the given node. In other words, it is the rightmost node in the left subtree of the given node, or the maximum element in the left subtree. Inorder Successor:Similarly, the inorder successor of a node in a BST is the node with the smallest key that is larger than the key of the given node. It is the leftmost node in the right subtree of the given node, or the minimum element in the right subtree. Illustration:We want to find the inorder predecessor and successor of the node with key 11.
Finding Inorder Predecessor and Successor:To find the inorder predecessor and successor for a given key in a BST, we can perform a modified search operation.
Implementation:Explanation:
Program Output: ![]() Complexity Analysis: The time complexity of finding the inorder predecessor and successor in a BST is O(h), where h is the height of the tree. In the worst-case scenario, when the tree is skewed, the height of the tree becomes equal to the number of nodes, resulting in O(n) time complexity. However, in well-balanced BSTs, the height is O(log n), leading to efficient operations. Conclusion:In conclusion, the algorithm efficiently finds the inorder predecessor and successor for a given key in a Binary Search Tree (BST) through recursive traversal. Leveraging the BST's structure, it determines the predecessor as the maximum value in the left subtree and the successor as the minimum value in the right subtree. With a time complexity of O(h), where h is the tree's height, it demonstrates optimal performance, especially in balanced trees, making it a reliable solution for various BST applications. |
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