How to Find the Shortest Path in a Binary Maze5 Jan 2025 | 7 min read In this problem we are given a binary matrix of size m-by-n. The matrix contains only 1s and 0s. The 1s in the matrix represent the path, and the 0s are the dead cells. We will be given two cell addresses. Our task is to find the shortest distance needed to go to the destination cell from the source cell. Let us see an example to understand the problem. Input: Output: The shortest path is 14 Approach - 1In this approach, we will perform DFS, and using backtracking, we will find the shortest path between the source and the destination cells. Here are the steps we will follow:
Code Output: The shortest path length is 14 Time Complexity: The time complexity of this approach is O(4 ^ M*N), where M and N are the dimensions of the matrix. Space Complexity: We have used a matrix to store the visited array; hence, the space complexity of this approach is O(M * N). Approach - 2In this approach, we will use the Breadth First Search algorithm to solve the problem. For the BFS, we will use the queue data structure. The queue will store two things for each node. The first thing is the coordinates of the cell, and the second thing is the distance of this cell from the source cell. The main idea of using the BFS algorithm is that, unlike the DFS algorithm, the BFS algorithm takes all paths at once. Hence, it will move one cell forward in each path. The path through which the destination cell will be reached for the first time will be the shortest path. And since we are storing the distance of the cell from the source cell in the queue, we will get the path length, too. Here is the algorithm of this approach.
Code Output: The shortest path length is 14 |
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