Copy Object Without Reference JavaScript18 Apr 2025 | 4 min read What is an Object?JavaScript uses objects to store data or functionality that is related in some way. An object is a collection of properties, which can include methods as well as simple data values. Essentially, objects are entities that have both state and behavior. For instance, cars, pens, bikes, chairs, glass, keyboards, monitors, and more can all be thought of as objects in JavaScript. In fact, everything in JavaScript is considered to be an object since it is an object-based language. How to Copy an Object in JavaScript?In JavaScript, copying an object is a simple task for primitive data types. But, we use various techniques such as deep cloning and shallow cloning for copying objects without reference. Deep Copying object JavaScript provides a feature called "deep copy" that allows us to create a duplicate of any object encountered. With deep copy, the copied object will not share anything with the original object, making it a complete copy. This means that any changes made to the copied object will not affect the original object. Shallow copying object In JavaScript, an object is copied according to the bitwise level. It means that the only first level of the object will be copied. How to Copy an Object without reference in JavaScript?In JavaScript, when we want to copy an object without the reference, then we use some methods such as "object.assign()" and "JSON.Parse()". When an object is copied using the assignment operator in JavaScript, the object and its value are stored in a variable on the right side. Using the object.assign() method to copy objectsIn JavaScript, the object.assign() method is used to copy objects without the reference. With the help of this method, we can copy the values and properties from one source object to a particular object that is targeted. Syntax Let's see the syntax so we can use the object.assign() method: Example Output: ![]() Using JSON.parse() method to Copy objectsIn JavaScript, we can use JSON.parse() and JSON.stringify() methods to perform deep copying. This allows us to copy an object without referencing it. Syntax Let's see the syntax of JSON.prase() method: Example Output: ![]() Benefits of Using Copy Object without ReferenceCopy objects without the reference can be beneficial for several reasons: Preventing Unintended Modifications In JavaScript, when we copy an object without the reference, we can separate instances. It means that any modifications made to the copied object won't affect the original one, which can help us to prevent unintended errors. Maintaining Data Integrity In JavaScript, by creating independent copies of the objects, we can ensure that each copy holds its own set of data. This can be helpful when we are working with a complex data structure or we pass the data between the different parts of our codebase. Isolating Changes We can also make changes to objects for a specific use case without changing the original object, and creating a copy of an object without reference allows you to isolate those changes. It will keep our code more modular and easy to maintain. Avoiding Shared State Issues In JavaScript, objects are passed by the reference by default. In simple words, if we pass an object to a function or assign it to another variable, they both point to the same objects in the memory. We can create copies of objects without reference helps avoid the shared state issues that can arise from unintentional object changes. Cloning Nested Objects When we deal with nested objects or arrays, copying without a reference it ensures that all the levels of the data structure are duplicated. It will prevent unexpected behavior that can occur when only the top-level object is copied. Overall, copying objects without reference in JavaScript promotes code stability, and data integrity, and helps prevent bugs related to unintended side effects of object mutations. Next TopicBinary-search-in-javascript |
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