Python Program for Smallest K digit number divisible by X

Python Program for Smallest K digit number divisible by X

Let's break down the problem:

Problem Statement: Given two numbers K and X, find the smallest K digit number that is divisible by X.

Approach:

  1. The smallest K digit number is 10^(K-1).
  2. Starting from this number, we'll keep incrementing the value until we find a number that is divisible by X.

Let's write the Python program for this:

Smallest K digit number divisible by X

1. Function to Find Number:

def find_smallest_k_digit_number_divisible_by_x(k, x): # Start from the smallest K digit number num = 10 ** (k - 1) # Keep incrementing the number until it is divisible by X while num % x != 0: num += 1 return num

2. Main Function:

def main(): k = 3 # Example value for K x = 7 # Example value for X result = find_smallest_k_digit_number_divisible_by_x(k, x) print(f"The smallest {k}-digit number divisible by {x} is: {result}") if __name__ == "__main__": main()

Output:

The smallest 3-digit number divisible by 7 is: 105

How it works:

  1. The function find_smallest_k_digit_number_divisible_by_x calculates the smallest K digit number and then checks its divisibility with X. If it's not divisible, the function keeps incrementing the number until it finds a number that is divisible.
  2. The main function sets the values for K and X and then uses the function to compute the result.

Note: This is a simple and straightforward method, but may not be the most efficient for large values of K and X. Depending on the use case, more efficient methods might need to be explored.

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