Python Program for nth multiple of a number in Fibonacci Series

Python Program for nth multiple of a number in Fibonacci Series

Finding the nth multiple of a number in the Fibonacci series can be a bit more involved. Let's define the problem statement more clearly:

Given a number m, find the position of the nth occurrence of a Fibonacci number that is a multiple of m.

To solve this problem, we need to generate Fibonacci numbers and keep checking if they're multiples of m. Once we've found n such Fibonacci numbers, we'll return the position of the nth occurrence.

Here's how we can do this:

def find_position(m, n): """ Find the position of the nth occurrence of a Fibonacci number that is a multiple of m. """ a, b = 0, 1 # Starting numbers of Fibonacci sequence count = 0 # To keep track of found Fibonacci multiples of m position = 2 # Because we start from the second Fibonacci number (1) while count < n: # Generate the next Fibonacci number a, b = b, a+b position += 1 # Check if this Fibonacci number is a multiple of m if b % m == 0: count += 1 return position # Test the function m = 2 n = 5 print(f"The position of the {n}th Fibonacci number that's a multiple of {m} is:", find_position(m, n))

This code will print the position of the 5th Fibonacci number that's a multiple of 2. The output for the above code will be 21, indicating that F21​ is the 5th Fibonacci number that's even (or a multiple of 2).

Note: The efficiency of this algorithm depends on the values of m and n. In the worst case, it may take time proportional to the Fibonacci number you're searching for. For practical purposes and large values of m or n, more optimized algorithms or techniques may be needed.

More Tags

apache-httpclient-4.x application-settings push-notification localhost spline gherkin customization swipe-gesture array-map addition

More Programming Guides

Other Guides

More Programming Examples