Python | Consecutive chunks Product

Python | Consecutive chunks Product

In this tutorial, we'll explore how to generate and compute the product of consecutive chunks of a list in Python.

Scenario: You have a list of numbers, and you need to find the product of numbers in consecutive chunks of a specified size.

Steps:

  1. Setup: Create a sample list of numbers.
  2. Generate Consecutive Chunks: Write a function that returns consecutive chunks of a specified size.
  3. Calculate Product: Write a function that computes the product of numbers in each chunk.
  4. Main Program: Combine the above steps and run the main program.

Tutorial:

1. Setup:

numbers = [2, 3, 4, 5, 6, 7, 8] 

2. Generate Consecutive Chunks:

def get_consecutive_chunks(lst, size): """Return consecutive chunks of a given size from the list.""" return [lst[i:i+size] for i in range(len(lst) - size + 1)] 

3. Calculate Product:

def product_of_chunk(chunk): """Return the product of all elements in a chunk.""" product = 1 for num in chunk: product *= num return product 

4. Main Program:

def main(): numbers = [2, 3, 4, 5, 6, 7, 8] chunk_size = 3 chunks = get_consecutive_chunks(numbers, chunk_size) products = [product_of_chunk(chunk) for chunk in chunks] for i, chunk in enumerate(chunks): print(f"Chunk: {chunk}, Product: {products[i]}") if __name__ == "__main__": main() 

When you run the program, it should display the product of consecutive chunks of size 3:

Chunk: [2, 3, 4], Product: 24 Chunk: [3, 4, 5], Product: 60 Chunk: [4, 5, 6], Product: 120 Chunk: [5, 6, 7], Product: 210 Chunk: [6, 7, 8], Product: 336 

You can modify the chunk_size variable to get the product of chunks of different sizes.


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