PyQt5 QCalendarWidget - Checking if it is visible to its ancestor

PyQt5 QCalendarWidget - Checking if it is visible to its ancestor

In PyQt5, if you want to check if a widget, such as QCalendarWidget, is visible to its ancestor, you can utilize the isVisibleTo() method. The isVisibleTo() method of a widget returns True if the widget is visible to the given ancestor, otherwise it returns False.

Here's how you can use it:

is_visible = calendarWidget.isVisibleTo(ancestorWidget)

Let's demonstrate this with a simple example:

import sys from PyQt5.QtWidgets import QApplication, QWidget, QVBoxLayout, QPushButton, QCalendarWidget class App(QWidget): def __init__(self): super().__init__() self.initUI() def initUI(self): layout = QVBoxLayout() self.calendar = QCalendarWidget(self) button = QPushButton("Check Visibility", self) button.clicked.connect(self.checkVisibility) layout.addWidget(self.calendar) layout.addWidget(button) self.setLayout(layout) self.setWindowTitle('PyQt5 QCalendarWidget Visibility') self.show() def checkVisibility(self): if self.calendar.isVisibleTo(self): print("Calendar is visible to its ancestor.") else: print("Calendar is not visible to its ancestor.") if __name__ == '__main__': app = QApplication(sys.argv) ex = App() sys.exit(app.exec_())

In the above code, we have a QCalendarWidget and a QPushButton. When you click the button, it checks if the QCalendarWidget is visible to its ancestor (which is the main App widget in this case) and prints a corresponding message to the console.

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