How to get path of an element in lxml?

How to get path of an element in lxml?

In lxml, you can get the path of an element using the getpath() method. This method returns an XPath expression that uniquely identifies the element within the XML or HTML tree. Here's how you can use it:

from lxml import etree # Create an example XML document xml = """ <root> <element1> <subelement1 /> <subelement2 /> </element1> <element2> <subelement3 /> </element2> </root> """ # Parse the XML string root = etree.fromstring(xml) # Find an element of interest element = root.find(".//subelement2") # Get the path of the element element_path = root.getpath(element) print("Element Path:", element_path)

In this example, we:

  1. Parse an XML document using lxml's etree.fromstring method.
  2. Use the find method to locate the subelement2 element within the XML tree.
  3. Call the getpath method on the root element, passing the found element as an argument to get its path.

The element_path variable will contain the XPath expression that represents the path to the subelement2 element within the XML tree. The output will look something like this:

Element Path: /root/element1/subelement2

This path uniquely identifies the element within the XML tree, allowing you to reference or locate it later using XPath queries.

Examples

    from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element element = root.xpath("//child[@id='1']")[0] # Get element's path path = root.getpath(element) print("Element's Path:", path) 
      from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element by attribute element = root.xpath("//child[@id='1']")[0] # Get element's path path = root.getpath(element) print("Element's Path:", path) 
        from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element element = root.xpath("//child[@id='1']")[0] # Get full XPath of element full_xpath = root.getelementpath(element) print("Full XPath of Element:", full_xpath) 
          from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element with specific attribute element = root.xpath("//child[@id='1']")[0] # Get element's path path = root.getpath(element) print("Element's Path:", path) 
            from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element element = root.xpath("//child[@id='1']")[0] # Get element's XPath xpath = etree.ElementTree(root).getpath(element) print("Element's XPath:", xpath) 
              from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element by attribute element = root.xpath("//child[@id='1']")[0] # Get element's path path = root.getpath(element) print("Element's Path:", path) 
                from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element element = root.xpath("//child[@id='1']")[0] # Get element's path path = root.getpath(element) print("Element's Path:", path) 
                  from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element with specific attribute element = root.xpath("//child[@id='1']")[0] # Get full XPath of element full_xpath = root.getelementpath(element) print("Full XPath of Element:", full_xpath) 
                    from lxml import etree # Sample XML document xml = """ <root> <parent> <child id="1"/> <child id="2"/> </parent> </root> """ # Parse XML root = etree.fromstring(xml) # Find element by attribute value element = root.xpath("//child[@id='1']")[0] # Get element's path path = root.getpath(element) print("Element's Path:", path)

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