Check whether a string is parsable into Long without try-catch in java?

Check whether a string is parsable into Long without try-catch in java?

In Java, you can check whether a string can be parsed into a long without using a try-catch block by using the Long.parseLong() method and checking for exceptions manually. Here's an example of how you can do it:

public class Main { public static void main(String[] args) { String input = "12345"; if (isParsableLong(input)) { long parsedValue = Long.parseLong(input); System.out.println("Parsed value: " + parsedValue); } else { System.out.println("Cannot parse the input as a long."); } } public static boolean isParsableLong(String input) { try { Long.parseLong(input); return true; } catch (NumberFormatException e) { return false; } } }

In this example, the isParsableLong method attempts to parse the input string as a long using Long.parseLong(). If parsing is successful, it returns true, indicating that the string is parsable as a long. If an exception (NumberFormatException) is thrown, it returns false. This way, you can avoid using a try-catch block in your main code and handle the parsing validation separately.

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